Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
This is the original cost matrix:
3 | 2 | 1 |
12 | 23 | 23 |
123 | 23 | 12 |
Subtract row minima
We subtract the row minimum from each row:
2 | 1 | 0 | (-1) |
0 | 11 | 11 | (-12) |
111 | 11 | 0 | (-12) |
Subtract column minima
We subtract the column minimum from each column:
2 | 0 | 0 |
0 | 10 | 11 |
111 | 10 | 0 |
(-1) |
Cover all zeros with a minimum number of lines
There are 3 lines required to cover all zeros:
2 | 0 | 0 | x |
0 | 10 | 11 | x |
111 | 10 | 0 | x |
The optimal assignment
Because there are 3 lines required, the zeros cover an optimal assignment:
2 | 0 | 0 |
0 | 10 | 11 |
111 | 10 | 0 |
This corresponds to the following optimal assignment in the original cost matrix:
3 | 2 | 1 |
12 | 23 | 23 |
123 | 23 | 12 |
The optimal value equals 26.
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