Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
51 | 84 | 86 | 74 |
11 | 86 | 61 | 31 |
26 | 25 | 70 | 23 |
42 | 19 | 71 | 69 |
Subtract row minima
We subtract the row minimum from each row:
0 | 33 | 35 | 23 | (-51) |
0 | 75 | 50 | 20 | (-11) |
3 | 2 | 47 | 0 | (-23) |
23 | 0 | 52 | 50 | (-19) |
Subtract column minima
We subtract the column minimum from each column:
0 | 33 | 0 | 23 |
0 | 75 | 15 | 20 |
3 | 2 | 12 | 0 |
23 | 0 | 17 | 50 |
(-35) |
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
0 | 33 | 0 | 23 | x |
0 | 75 | 15 | 20 | x |
3 | 2 | 12 | 0 | x |
23 | 0 | 17 | 50 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
0 | 33 | 0 | 23 |
0 | 75 | 15 | 20 |
3 | 2 | 12 | 0 |
23 | 0 | 17 | 50 |
This corresponds to the following optimal assignment in the original cost matrix:
51 | 84 | 86 | 74 |
11 | 86 | 61 | 31 |
26 | 25 | 70 | 23 |
42 | 19 | 71 | 69 |
The optimal value equals 139.
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