Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
55 | 76 | 57 | 35 |
6 | 89 | 72 | 10 |
32 | 45 | 16 | 33 |
65 | 95 | 21 | 27 |
Subtract row minima
We subtract the row minimum from each row:
20 | 41 | 22 | 0 | (-35) |
0 | 83 | 66 | 4 | (-6) |
16 | 29 | 0 | 17 | (-16) |
44 | 74 | 0 | 6 | (-21) |
Subtract column minima
We subtract the column minimum from each column:
20 | 12 | 22 | 0 |
0 | 54 | 66 | 4 |
16 | 0 | 0 | 17 |
44 | 45 | 0 | 6 |
(-29) |
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
20 | 12 | 22 | 0 | x |
0 | 54 | 66 | 4 | x |
16 | 0 | 0 | 17 | x |
44 | 45 | 0 | 6 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
20 | 12 | 22 | 0 |
0 | 54 | 66 | 4 |
16 | 0 | 0 | 17 |
44 | 45 | 0 | 6 |
This corresponds to the following optimal assignment in the original cost matrix:
55 | 76 | 57 | 35 |
6 | 89 | 72 | 10 |
32 | 45 | 16 | 33 |
65 | 95 | 21 | 27 |
The optimal value equals 107.
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