Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
43 | 12 | 62 | 31 |
9 | 87 | 68 | 3 |
91 | 82 | 67 | 92 |
17 | 46 | 80 | 9 |
Subtract row minima
We subtract the row minimum from each row:
31 | 0 | 50 | 19 | (-12) |
6 | 84 | 65 | 0 | (-3) |
24 | 15 | 0 | 25 | (-67) |
8 | 37 | 71 | 0 | (-9) |
Subtract column minima
We subtract the column minimum from each column:
25 | 0 | 50 | 19 |
0 | 84 | 65 | 0 |
18 | 15 | 0 | 25 |
2 | 37 | 71 | 0 |
(-6) |
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
25 | 0 | 50 | 19 | x |
0 | 84 | 65 | 0 | x |
18 | 15 | 0 | 25 | x |
2 | 37 | 71 | 0 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
25 | 0 | 50 | 19 |
0 | 84 | 65 | 0 |
18 | 15 | 0 | 25 |
2 | 37 | 71 | 0 |
This corresponds to the following optimal assignment in the original cost matrix:
43 | 12 | 62 | 31 |
9 | 87 | 68 | 3 |
91 | 82 | 67 | 92 |
17 | 46 | 80 | 9 |
The optimal value equals 97.
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