Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
95 | 59 | 59 | 93 |
82 | 95 | 55 | 17 |
17 | 85 | 21 | 74 |
99 | 46 | 9 | 29 |
Subtract row minima
We subtract the row minimum from each row:
36 | 0 | 0 | 34 | (-59) |
65 | 78 | 38 | 0 | (-17) |
0 | 68 | 4 | 57 | (-17) |
90 | 37 | 0 | 20 | (-9) |
Subtract column minima
Because each column contains a zero, subtracting column minima has no effect.
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
36 | 0 | 0 | 34 | x |
65 | 78 | 38 | 0 | x |
0 | 68 | 4 | 57 | x |
90 | 37 | 0 | 20 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
36 | 0 | 0 | 34 |
65 | 78 | 38 | 0 |
0 | 68 | 4 | 57 |
90 | 37 | 0 | 20 |
This corresponds to the following optimal assignment in the original cost matrix:
95 | 59 | 59 | 93 |
82 | 95 | 55 | 17 |
17 | 85 | 21 | 74 |
99 | 46 | 9 | 29 |
The optimal value equals 102.
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