Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
80 | 60 | 9 |
45 | 31 | 44 |
78 | 28 | 75 |
Subtract row minima
We subtract the row minimum from each row:
71 | 51 | 0 | (-9) |
14 | 0 | 13 | (-31) |
50 | 0 | 47 | (-28) |
Subtract column minima
We subtract the column minimum from each column:
57 | 51 | 0 |
0 | 0 | 13 |
36 | 0 | 47 |
(-14) |
Cover all zeros with a minimum number of lines
There are 3 lines required to cover all zeros:
57 | 51 | 0 | x |
0 | 0 | 13 | x |
36 | 0 | 47 | x |
The optimal assignment
Because there are 3 lines required, the zeros cover an optimal assignment:
57 | 51 | 0 |
0 | 0 | 13 |
36 | 0 | 47 |
This corresponds to the following optimal assignment in the original cost matrix:
80 | 60 | 9 |
45 | 31 | 44 |
78 | 28 | 75 |
The optimal value equals 82.
HungarianAlgorithm.com © 2013-2024