Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
39 | 88 | 26 | 99 |
8 | 93 | 17 | 70 |
19 | 63 | 86 | 8 |
69 | 23 | 65 | 26 |
Subtract row minima
We subtract the row minimum from each row:
13 | 62 | 0 | 73 | (-26) |
0 | 85 | 9 | 62 | (-8) |
11 | 55 | 78 | 0 | (-8) |
46 | 0 | 42 | 3 | (-23) |
Subtract column minima
Because each column contains a zero, subtracting column minima has no effect.
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
13 | 62 | 0 | 73 | x |
0 | 85 | 9 | 62 | x |
11 | 55 | 78 | 0 | x |
46 | 0 | 42 | 3 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
13 | 62 | 0 | 73 |
0 | 85 | 9 | 62 |
11 | 55 | 78 | 0 |
46 | 0 | 42 | 3 |
This corresponds to the following optimal assignment in the original cost matrix:
39 | 88 | 26 | 99 |
8 | 93 | 17 | 70 |
19 | 63 | 86 | 8 |
69 | 23 | 65 | 26 |
The optimal value equals 65.
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